5.2.9. nvector.core.mean_horizontal_position¶
-
mean_horizontal_position
(n_EB_E)[source]¶ Returns the n-vector of the horizontal mean position.
- Parameters
- n_EB_E: 3 x n array
n-vectors [no unit] of positions Bi, decomposed in E.
- Returns
- p_EM_E: 3 x 1 array
n-vector [no unit] of the mean positions of all Bi, decomposed in E.
Examples
Example 7: “Mean position”
Three positions A, B, and C are given as n-vectors n_EA_E, n_EB_E, and n_EC_E. Find the mean position, M, given as n_EM_E. Note that the calculation is independent of the depths of the positions.
- Solution:
>>> import numpy as np >>> import nvector as nv >>> from nvector import rad, deg
>>> n_EA_E = nv.lat_lon2n_E(rad(90), rad(0)) >>> n_EB_E = nv.lat_lon2n_E(rad(60), rad(10)) >>> n_EC_E = nv.lat_lon2n_E(rad(50), rad(-20))
>>> n_EM_E = nv.unit(n_EA_E + n_EB_E + n_EC_E)
- or
>>> n_EM_E = nv.mean_horizontal_position(np.hstack((n_EA_E, n_EB_E, n_EC_E)))
>>> lat, lon = nv.n_E2lat_lon(n_EM_E) >>> lat, lon = deg(lat), deg(lon) >>> msg = 'Ex7: Pos M: lat, lon = {:4.2f}, {:4.2f} deg' >>> msg.format(lat[0], lon[0]) 'Ex7: Pos M: lat, lon = 67.24, -6.92 deg'